Matematika Sekolah Dasar Hi .. :)Y = 2³ + 2²O = 1²U = √4Tentukan :Y × O + U​

scottybauchulv – March 08, 2023

Hi .. :)

Y = 2³ + 2²
O = 1²
U = √4
Tentukan :
Y × O + U
​

Jawaban:

Penyelesaian :

Dik :

• Y = 2³ + 2²

• O = 1²

• U = √4

Dit :

• Y × O + U = ? ?

Jawab :

Dik :

=> Y = 2³ + 2²

• 2³ + 2²

• = ( 2 × 2 × 2 ) + ( 2 × 2 )

• = ( 4 × 2 ) + 4

• = 8 + 4

• = 12

=> 1²

• 1²

• = 1 × 1

• = 1

=> U = √4

[tex] \sqrt{ \: 4 \: } = \sqrt{2 \times 2} = 2[/tex]

Jawab 2 :

• Y × O + U

• = 12 × 1 + 2

• = ( 12 × 1 ) + 2

• = 12 + 2

• = 14

Y = 2³ + 2²

Y = (2 × 2 × 2) + (2 × 2)

Y = 8 + 4

Y = 12

O = 1²

O = (1 × 1)

O = 1

U = √4

U = 2

12 × 1 + 2

12 + 2

= 14

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